# Sum square difference

*Author: polettix*

https://projecteuler.net/problem=6

The sum of the squares of the first ten natural numbers is,

1**2 + 2**2 + ... + 10**2 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)**2 = 55**2 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

Source code: prob006-polettix.pl

use v6; # Upper bound optionally taken from command line, defaults to # challenge's request my $upper = shift(@*ARGS) || 100; # This is quite straightforward: the sum of the first N positive # integers is easily computed as (N + 1) * N / 2, hence the square # is straightforward. We then subtract the square of each single # one to get the final result. my $result = (($upper + 1) * $upper / 2) ** 2; $result -= $_ ** 2 for 1 .. $upper; say $result;